From 83e85f6a0837c9cf39146c4798a8583aecba5da3 Mon Sep 17 00:00:00 2001 From: Mark Whitley Date: Tue, 25 Jul 2000 20:48:44 +0000 Subject: [PATCH] Modified print_subst_w_backrefs() so it will print backslash escaped characters properly, just like GNU sed. --- editors/sed.c | 6 ++++++ sed.c | 6 ++++++ 2 files changed, 12 insertions(+) diff --git a/editors/sed.c b/editors/sed.c index 69a5e0324..665471913 100644 --- a/editors/sed.c +++ b/editors/sed.c @@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat fputc(line[j], stdout); } + /* if we find a backslash escaped character, print the character */ + else if (replace[i] == '\\') { + ++i; + fputc(replace[i], stdout); + } + /* if we find an unescaped '&' print out the whole matched text. * fortunately, regmatch[0] contains the indicies to the whole matched * expression (kinda seems like it was designed for just such a diff --git a/sed.c b/sed.c index 69a5e0324..665471913 100644 --- a/sed.c +++ b/sed.c @@ -500,6 +500,12 @@ static void print_subst_w_backrefs(const char *line, const char *replace, regmat fputc(line[j], stdout); } + /* if we find a backslash escaped character, print the character */ + else if (replace[i] == '\\') { + ++i; + fputc(replace[i], stdout); + } + /* if we find an unescaped '&' print out the whole matched text. * fortunately, regmatch[0] contains the indicies to the whole matched * expression (kinda seems like it was designed for just such a -- 2.25.1