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If n0 == d0, we must alway compute 'rem' "by hand"
author
Bodo Möller
<bodo@openssl.org>
Tue, 1 Feb 2000 11:10:54 +0000
(11:10 +0000)
committer
Bodo Möller
<bodo@openssl.org>
Tue, 1 Feb 2000 11:10:54 +0000
(11:10 +0000)
crypto/bn/bn_div.c
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diff --git
a/crypto/bn/bn_div.c
b/crypto/bn/bn_div.c
index 928773af1c9e1edc1a883b2b880e9f8d7749c4ec..f15eced0cfa0fea8fb83e731b6ee1351b88ac60c 100644
(file)
--- a/
crypto/bn/bn_div.c
+++ b/
crypto/bn/bn_div.c
@@
-235,8
+235,13
@@
int BN_div(BIGNUM *dv, BIGNUM *rm, const BIGNUM *num, const BIGNUM *divisor,
n0=wnump[0];
n1=wnump[-1];
if (n0 == d0)
+ {
q=BN_MASK2;
- else
+#ifdef REMAINDER_IS_ALREADY_CALCULATED /* in this case it isn't */
+ rem=(n1-q*d0)&BN_MASK2;
+#endif
+ }
+ else /* n0 < d0 */
#if defined(BN_LLONG) && defined(BN_DIV2W) && !defined(bn_div_words)
q=(BN_ULONG)(((((BN_ULLONG)n0)<<BN_BITS2)|n1)/d0);
#else