Some versions of the Microsoft TLS stack have problems when the DHE public key
is encoded with fewer bytes than the DHE prime. (Backported from master)
Reviewed-by: Matt Caswell <matt@openssl.org>
Reviewed-by: Rich Salz <rsalz@openssl.org>
(Merged from https://github.com/openssl/openssl/pull/1350)
unsigned int u;
#endif
#ifndef OPENSSL_NO_DH
+# ifdef OPENSSL_NO_RSA
+ int j;
+# endif
DH *dh = NULL, *dhp;
#endif
#ifndef OPENSSL_NO_ECDH
if ((i == 2) && (type & SSL_kSRP))
n += 1 + nr[i];
else
+#endif
+#ifndef OPENSSL_NO_DH
+ /*
+ * for interoperability with some versions of the Microsoft TLS
+ * stack, we need to zero pad the DHE pub key to the same length
+ * as the prime, so use the length of the prime here
+ */
+ if ((i == 2) && (type & (SSL_kEDH)))
+ n += 2 + nr[0];
+ else
#endif
n += 2 + nr[i];
}
*p = nr[i];
p++;
} else
+#endif
+#ifndef OPENSSL_NO_DH
+ /*
+ * for interoperability with some versions of the Microsoft TLS
+ * stack, we need to zero pad the DHE pub key to the same length
+ * as the prime
+ */
+ if ((i == 2) && (type & (SSL_kEDH))) {
+ s2n(nr[0], p);
+ for (j = 0; j < (nr[0] - nr[2]); ++j) {
+ *p = 0;
+ ++p;
+ }
+ } else
#endif
s2n(nr[i], p);
BN_bn2bin(r[i], p);