static NOINLINE half_t isqrt_odd(wide_t N)
{
half_t s = isqrt(N);
- if (s && !(s & 1)) /* even? */
- s--;
+ /* Subtract 1 from even s, odd s won't change: */
+ /* (doesnt work for zero, but we know that s != 0 here) */
+ s = (s - 1) | 1;
return s;
}
N >>= 1;
}
+ /* The code needs to be optimized for the case where
+ * there are large prime factors. For example,
+ * this is not hard:
+ * 8262075252869367027 = 3 7 17 23 47 101 113 127 131 137 823
+ * (the largest factor to test is only ~sqrt(823) = 28)
+ * but this is:
+ * 18446744073709551601 = 53 348051774975651917
+ * the last factor requires testing up to
+ * 589959129 - about 100 million iterations.
+ */
max_factor = isqrt_odd(N);
count3 = 3;
count5 = 6;
* 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47...
* ^ ^ ^ ^ ^ ^ ^ _ ^ ^ _ ^ ^ ^ ^
* (^ = primes, _ = would-be-primes-if-not-divisible-by-5)
+ * The numbers with space under them are excluded by sieve 3.
*/
count7--;
count5--;
count3--;
if (count3 && count5 && count7)
continue;
- if (count3 == 0)
+ /*
+ * "factor" is multiple of 3 33% of the time (count3 reached 0),
+ * else, multiple of 5 13% of the time,
+ * else, multiple of 7 7.6% of the time.
+ * Cumulatively, with 3,5,7 sieving we are here 54.3% of the time.
+ */
+ if (count3 == 0) {
count3 = 3;
- if (count5 == 0)
+ }
+ if (count5 == 0) {
count5 = 5;
- if (count7 == 0)
+ }
+ if (count7 == 0) {
count7 = 7;
+ }
goto next_factor;
}
end: