On some platforms (e.g. x86), the return value of dev_get_addr() can't
be assigned to a pointer type variable directly. As there might be a
difference between the size of fdt_addr_t and the pointer type. On
x86 for example, "fdt_addr_t" is 64bit but "void *" only 32bit. So
assigning the register base directly in dev_get_addr() results in this
compilation warning:
warning: cast to pointer from integer of different size
This patch introduces the new function dev_get_addr_ptr() that
returns a pointer to the 'reg' address that can be used by drivers
in this case.
Signed-off-by: Stefan Roese <sr@denx.de>
Reviewed-by: Simon Glass <sjg@chromium.org>
Reviewed-by: Bin Meng <bmeng.cn@gmail.com>
return dev_get_addr_index(dev, 0);
}
+void *dev_get_addr_ptr(struct udevice *dev)
+{
+ return (void *)(uintptr_t)dev_get_addr_index(dev, 0);
+}
+
bool device_has_children(struct udevice *dev)
{
return !list_empty(&dev->child_head);
*/
fdt_addr_t dev_get_addr(struct udevice *dev);
+/**
+ * dev_get_addr_ptr() - Return pointer to the address of the reg property
+ * of a device
+ *
+ * @dev: Pointer to a device
+ *
+ * @return Pointer to addr, or NULL if there is no such property
+ */
+void *dev_get_addr_ptr(struct udevice *dev);
+
/**
* dev_get_addr_index() - Get the indexed reg property of a device
*